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4p^2-5p-51=0
a = 4; b = -5; c = -51;
Δ = b2-4ac
Δ = -52-4·4·(-51)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-29}{2*4}=\frac{-24}{8} =-3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+29}{2*4}=\frac{34}{8} =4+1/4 $
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